/** * Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as * one sorted array. * * Note: * You may assume that nums1 has enough space (size that is greater or equal to * m + n) to hold additional elements from nums2. The number of elements * initialized in nums1 and nums2 are m and n respectively. * */ public class MergeSortedArray88 { public void merge(int[] nums1, int m, int[] nums2, int n) { if (n == 0) return; int i = m-1; int j = n-1; while (i >= 0 && j >= 0) { if (nums1[i] >= nums2[j]) { nums1[i+j+1] = nums1[i]; i--; } else { nums1[i+j+1] = nums2[j]; j--; } } while (j >= 0) { nums1[j] = nums2[j]; j--; } } /** * https://leetcode.com/problems/merge-sorted-array/discuss/29505/1-Line-Solution */ public void merge2(int[] nums1, int m, int[] nums2, int n) { while (n > 0) nums1[m+n-1] = (m == 0 || nums2[n-1] > nums1[m-1]) ? nums2[--n] : nums1[--m]; } }